Which of the following is true regarding glyc | vedclass

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Question

(A) Glycolysis is the process where one molecule of $6$-carbon glucose is broken down into two molecules of $3$-carbon pyruvic acid.This process occur

Vedclass · Accepted Answer

Only $I$

Vedclass · Answer

(A) Glycolysis is the process where one molecule of $6$-carbon glucose is broken down into two molecules of $3$-carbon pyruvic acid.This process occurs in the cytosol of the cell.During glycolysis,$2$ molecules of $ATP$ are produced (net gain),and $2$ molecules of $NAD^+$ are reduced to $NADH$ for every glucose molecule.Since $NADH$ produced in glycolysis enters the electron transport chain $(ETC)$ to produce $ATP$,it has a direct connection with the $ETC$.Therefore,only statement $I$ is correct.

Column-$I$ (Molecules)	Column-$II$ (Number of Carbon and Phosphorus)
$P$. Fructose $1, 6$-bisphosphate	$I$. $(C-3), (P-2)$
$Q$. Glucose-$6$-phosphate	$II$. $(C-3), (P-1)$
$R$. $DHAP$	$III$. $(C-6), (P-2)$
$S$. $BPGA$	$IV$. $(C-6), (P-1)$

Which of the following is true regarding glycolysis?
$I.$ Takes place in cytosol
$II.$ Produces no $ATP$
$III.$ Has no connection with electron transport chain
$IV.$ Reduces three molecules of $NAD^+$ for every glucose molecule processed
Choose the correct option.

Similar Questions

$EMP$ pathway is also known as:

How many pyruvate molecules are produced by the oxidation of $1$ glucose molecule?

Match the following columns:
Column-$I$ (Molecules) Column-$II$ (Number of Carbon and Phosphorus)
$P$. Fructose $1, 6$-bisphosphate $I$. $(C-3), (P-2)$
$Q$. Glucose-$6$-phosphate $II$. $(C-3), (P-1)$
$R$. $DHAP$ $III$. $(C-6), (P-2)$
$S$. $BPGA$ $IV$. $(C-6), (P-1)$

What is the end product of glycolysis?

Provide the full names for the following abbreviations:
$(1)$ $PEP$
$(2)$ $TPP$

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Which of the following is true regarding glycolysis?$I.$ Takes place in cytosol$II.$ Produces no $ATP$$III.$ Has no connection with electron transport chain$IV.$ Reduces three molecules of $NAD^+$ for every glucose molecule processedChoose the correct option.