Which of the following molecules possesses a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the hybridization of carbon atoms in the given molecules,we look at the structure of $CH_2=CH-C\equiv CH$ (Butenyne).In Butenyne,the

Vedclass · Accepted Answer

Butenyne

Vedclass · Answer

(A) To determine the hybridization of carbon atoms in the given molecules,we look at the structure of $CH_2=CH-C\equiv CH$ (Butenyne).In Butenyne,the structure is $CH_2=CH-C\equiv CH$.The carbon atoms are numbered as $C_1=C_2-C_3\equiv C_4$.$C_1$ is $sp^2$ hybridized,$C_2$ is $sp^2$ hybridized,$C_3$ is $sp$ hybridized,and $C_4$ is $sp$ hybridized.The bond between $C_2$ and $C_3$ is formed by the overlap of an $sp^2$ orbital from $C_2$ and an $sp$ orbital from $C_3$.Therefore,Butenyne contains an $sp^2-sp$ sigma bond.

Which of the following molecules possesses a bond formed by $sp^2-sp$ orbital overlap?

Similar Questions

The strongest bond is formed when atomic orbitals undergo:

Indicate the $\sigma$ and $\pi$ bonds in the following molecules:
$C_{6}H_{6}, C_{6}H_{12}, CH_{2}Cl_{2}, CH_{2}=C=CH_{2}, CH_{3}NO_{2}, HCONHCH_{3}$

In which of the following ions is $p\pi - d\pi$ overlap present?

Which of the following types of orbital overlapping results in the formation of a $\pi$ bond?

The nodal plane in an ethylene $(C_2H_4)$ molecule is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module