Which of the following molecules has a centra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The hybridization of the central atom can be determined using the formula: $	ext{Steric Number} = (	ext{Number of bonded atoms}) + (	ext{Number

Vedclass · Accepted Answer

$BCl_3$

Vedclass · Answer

(B) The hybridization of the central atom can be determined using the formula: $	ext{Steric Number} = (	ext{Number of bonded atoms}) + (	ext{Number of lone pairs})$.For $BeF_2$: $	ext{Steric Number} = 2 + 0 = 2$ ($sp$ hybridization).For $BCl_3$: $	ext{Steric Number} = 3 + 0 = 3$ ($sp^2$ hybridization).For $C_2H_2$: The carbon atoms have a steric number of $2$ ($sp$ hybridization).For $NH_3$: $	ext{Steric Number} = 3 + 1 = 4$ ($sp^3$ hybridization).Thus,the molecule with $sp^2$ hybridization is $BCl_3$.

List-$I$ (Species)	List-$II$ (Hybrid Orbitals)
$(a)$ $SF_{4}$	$(i)$ $sp^{3}d^{2}$
$(b)$ $IF_{5}$	$(ii)$ $d^{2}sp^{3}$
$(c)$ $NO_{2}^{+}$	$(iii)$ $sp^{3}d$
$(d)$ $NH_{4}^{+}$	$(iv)$ $sp^{3}$
	$(v)$ $sp$

Which of the following molecules has a central atom that adopts $sp^2$ hybridization?

Similar Questions

What is meant by hybridisation of atomic orbitals? Describe the shapes of $sp$,$sp^{2}$,$sp^{3}$ hybrid orbitals.

The species in which the nitrogen atom is in a state of $sp$ hybridisation is

The correct order regarding electronegativity of hybrid orbitals of carbon is

Match List-$I$ with List-$II$ :

List-$I$ (Species) List-$II$ (Hybrid Orbitals)

$(a)$ $SF_{4}$ $(i)$ $sp^{3}d^{2}$

$(b)$ $IF_{5}$ $(ii)$ $d^{2}sp^{3}$

$(c)$ $NO_{2}^{+}$ $(iii)$ $sp^{3}d$

$(d)$ $NH_{4}^{+}$ $(iv)$ $sp^{3}$

$(v)$ $sp$

Choose the correct answer from the options given below :

The order of electronegativity of carbon in $sp$,$sp^{2}$ and $sp^{3}$ hybridised states follows:

Vedclass Test Series

Exam Paper Generator

Online Exam Module