Which of the following molecules has a regula | vedclass

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(A) $1$. $SiCl_4$: The central atom $Si$ has $4$ valence electrons and forms $4$ bonds with $Cl$ atoms. It undergoes $sp^3$ hybridization with $0$ lon

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$SiCl_4$

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(A) $1$. $SiCl_4$: The central atom $Si$ has $4$ valence electrons and forms $4$ bonds with $Cl$ atoms. It undergoes $sp^3$ hybridization with $0$ lone pairs,resulting in a regular tetrahedral geometry.$2$. $SF_4$: The central atom $S$ has $6$ valence electrons,forms $4$ bonds,and has $1$ lone pair. It undergoes $sp^3d$ hybridization,resulting in a see-saw geometry (distorted).$3$. $BrF_5$: The central atom $Br$ has $7$ valence electrons,forms $5$ bonds,and has $1$ lone pair. It undergoes $sp^3d^2$ hybridization,resulting in a square pyramidal geometry (distorted).$4$. $XeF_4$: The central atom $Xe$ has $8$ valence electrons,forms $4$ bonds,and has $2$ lone pairs. It undergoes $sp^3d^2$ hybridization,resulting in a square planar geometry (distorted due to lone pairs).$5$. Therefore,only $SiCl_4$ has a regular geometry.

List-$I$	List-$II$
$(1)$ ${H_3O^+}$	$(A)$ Linear
$(2)$ ${HC \equiv CH}$	$(B)$ Angular
$(3)$ ${ClO_2^-}$	$(C)$ Tetrahedral
$(4)$ ${NH_4^+}$	$(D)$ Trigonal bipyramidal
	$(E)$ Pyramidal

Which of the following molecules has a regular geometry as expected?

Similar Questions

Which among the following molecules is not perfectly flat?

Match the species given in List-$I$ with their correct geometric shapes given in List-$II$.

List-$I$ List-$II$

$(1)$ ${H_3O^+}$ $(A)$ Linear

$(2)$ ${HC \equiv CH}$ $(B)$ Angular

$(3)$ ${ClO_2^-}$ $(C)$ Tetrahedral

$(4)$ ${NH_4^+}$ $(D)$ Trigonal bipyramidal

$(E)$ Pyramidal

In the reaction given below,what are the geometries of $BCl_3$ and $X$ respectively?
$BCl_3 + NH_3 \rightarrow X$

In both water $(H_{2}O)$ and dimethyl ether $((CH_{3})_{2}O)$,the oxygen atom is the central atom and has the same hybridization,yet they have different bond angles. Which one has a greater bond angle? Give a reason.

Explain the shape of $BrF_{5}$.

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