Which of the following molecules represents t | vedclass

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(B) The correct molecule is $CH_{2}=CH-C \equiv CH$.
$1$. The first carbon $(CH_{2}=)$ is bonded to two hydrogens and one carbon via a double bond,so

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$CH_{2}=CH-C \equiv CH$

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(B) The correct molecule is $CH_{2}=CH-C \equiv CH$.
$1$. The first carbon $(CH_{2}=)$ is bonded to two hydrogens and one carbon via a double bond,so it has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridisation.
$2$. The second carbon $(-CH-)$ is bonded to one hydrogen,one carbon via a double bond,and one carbon via a single bond,resulting in $sp^2$ hybridisation.
$3$. The third carbon $(-C \equiv)$ is bonded to one carbon via a single bond and one carbon via a triple bond,resulting in $sp$ hybridisation.
$4$. The fourth carbon $(\equiv CH)$ is bonded to one carbon via a triple bond and one hydrogen,resulting in $sp$ hybridisation.
Thus,the order is $sp^2, sp^2, sp, sp$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

Which of the following molecules represents the order of hybridisation $sp^2, sp^2, sp, sp$ from left to right for the carbon atoms?

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Which one amongst the following possesses an $sp$ hybridized carbon in its structure?

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

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