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(C) In the given graph,the $y$-axis represents time $(t)$ and the $x$-axis represents displacement $(s)$.For a physical motion,time must always increa

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The graph shown is impossible.

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(C) In the given graph,the $y$-axis represents time $(t)$ and the $x$-axis represents displacement $(s)$.For a physical motion,time must always increase as the object moves.In the given graph,as the object moves from $B$ to $C$ and then to $D$,the displacement $s$ decreases while time $t$ continues to increase.However,at any given time $t$,an object can only have one position $s$.Looking at the graph,for a single value of time $t$ (on the vertical axis),there are multiple values of displacement $s$ (on the horizontal axis) possible,which is physically impossible for a single object in motion.Furthermore,the graph shows the object moving backward in displacement,which is possible,but the specific shape implies that for a single time instant,the object is at multiple positions,or more accurately,the slope $\frac{dt}{ds}$ is plotted instead of $\frac{ds}{dt}$.Since time cannot decrease or be multi-valued for a single position,this graph is physically impossible.

Which of the following options is correct for the object having a straight-line motion represented by the following graph?

Similar Questions

Fill in the blanks:
$(a)$ The path length is always ............ .
$(b)$ The slope of the velocity-time graph for an object moving with acceleration is ............ .
$(c)$ If the velocity-time graph is parallel to the time-axis,the object is ............ .

Which of the following displacement $(X)$ time graphs is not possible?

Refer to the graph in the figure. Match the following:

The figure shows a velocity-time graph of a particle moving along a straight line. The correct acceleration-time graph of the particle is shown as:

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