Which of the following options is the correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The correct order of stability is $I > II > III$.Structure $I$ is a benzyl carbocation,which is highly stabilized by resonance with the benzene ri

Vedclass · Accepted Answer

$I > II > III$

Vedclass · Answer

(A) The correct order of stability is $I > II > III$.Structure $I$ is a benzyl carbocation,which is highly stabilized by resonance with the benzene ring.Structure $II$ is a secondary allylic carbocation,which is stabilized by both resonance and hyperconjugation.Structure $III$ is a tertiary carbocation,which is stabilized by the inductive effect and hyperconjugation of nine $\alpha$-hydrogens. However,resonance stabilization in $I$ and $II$ generally outweighs the inductive/hyperconjugative stabilization of $III$ in this context.

Which of the following options is the correct order of relative stabilities of cations $I$,$II$,and $III$ as shown below (most stable first)?
$(I) \, C_6H_5CH_2^+$
$(II) \, CH_2=CH-CH_2-CH^+-CH_3$
$(III) \, (CH_3)_3C^+$

Similar Questions

Which equilibrium is not rapid at room temperature?

The Fischer projection formula of the given structure is:

Which carbocation is the most stabilized?

Which of the following statements is correct regarding the given compounds $(1)$,$(2)$,and $(3)$?

For the following Newman projection,identify the corresponding sawhorse projection.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following options is the correct order of relative stabilities of cations $I$,$II$,and $III$ as shown below (most stable first)?$(I) \, C_6H_5CH_2^+$$(II) \, CH_2=CH-CH_2-CH^+-CH_3$$(III) \, (CH_3)_3C^+$