Which of the following order(s) is/are correc | vedclass

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(C) $1$. $IE_1$ order: $Li (2s^1) < B (2p^1) < Be (2s^2) < C (2p^2)$. The correct order is $Li < B < Be < C$. Thus,$(1)$ is incorrect.$2$. Reducing po

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$2, 3, 4$

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(C) $1$. $IE_1$ order: $Li (2s^1) $2$. Reducing power in gaseous state is inversely proportional to $IE_1$. Since $IE_1$ decreases down the group,reducing power increases. Thus,$Li $3$. In aqueous solution,ionic mobility is inversely proportional to the hydrated radius. $Li^+$ has the smallest size but the largest hydrated radius due to high charge density. Thus,$Li^+ $4$. Electron affinity $(EA)$ order for group $16$ is $S > Se > Te > Po > O$. Thus,$S > Se > Te > O$ is correct. $(4)$ is correct.

Which of the following order$(s)$ is/are correct?
$(1) Li < Be < B < C$ $(IE_1)$
$(2) Li < Na < K < Rb < Cs$ (Reducing power in gaseous state)
$(3) Li^{+} < Na^{+} < K^{+} < Rb^{+} < Cs^{+}$ (Ionic mobility in aqueous solution)
$(4) S > Se > Te > O$ $(EA)$

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Which of the following order$(s)$ is/are correct?$(1) Li < Be < B < C$ $(IE_1)$$(2) Li < Na < K < Rb < Cs$ (Reducing power in gaseous state)$(3) Li^{+} < Na^{+} < K^{+} < Rb^{+} < Cs^{+}$ (Ionic mobility in aqueous solution)$(4) S > Se > Te > O$ $(EA)$