Which of the following orders is correct?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. For ionic size: $P^{3-} (1.71 \ \mathring{A}) > S^{2-} (1.40 \ \mathring{A}) > Ca^{2+} (1.00 \ \mathring{A}) > K^{+} (1.38 \ \mathri

Vedclass · Accepted Answer

$Al^{3+}_{(aq)} > Mg^{2+}_{(aq)} > Na^{+}_{(aq)}$ : Hydrated size

Vedclass · Answer

(C) $1$. For ionic size: $P^{3-} (1.71 \ \mathring{A}) > S^{2-} (1.40 \ \mathring{A}) > Ca^{2+} (1.00 \ \mathring{A}) > K^{+} (1.38 \ \mathring{A})$. The given order is incorrect.
$2$. For electrical conductance in aqueous solution: Conductance depends on ionic mobility. Smaller ions in the gas phase have higher charge density,leading to greater hydration. Thus,$Na^{+}_{(aq)}$ is the most hydrated and has the lowest mobility and conductance. The correct order is $Cs^{+} > Rb^{+} > K^{+} > Na^{+}$. The given order is incorrect.
$3$. For hydrated size: Higher charge density leads to more hydration. $Al^{3+}$ has the highest charge density,followed by $Mg^{2+}$ and $Na^{+}$. Thus,the hydrated size order is $Al^{3+}_{(aq)} > Mg^{2+}_{(aq)} > Na^{+}_{(aq)}$. This is correct.
$4$. For ionic mobility: Smaller hydrated ions have higher mobility. $F^{-}$ is most hydrated,so it has the lowest mobility. The order should be $I^{-} > Br^{-} > F^{-}$. The given order is incorrect.

Similar Questions

The change in enthalpy $[\Delta H]$ in $kJ\ mol^{-1}$ for the reaction is $Mg + 2F \rightarrow MgF_2$. Given: $EA$ of $F = 328\ kJ\ mol^{-1}$, $IE_1$ of $Mg = 737\ kJ\ mol^{-1}$, $IE_2$ of $Mg = 1451\ kJ\ mol^{-1}$.

The number of the following pairs of elements which exhibit a diagonal relationship is:
$1. B \text{ and } Si$
$2. Be \text{ and } Al$
$3. Li \text{ and } Mg$
$4. Al \text{ and } S$

Which of the following statements is correct regarding the following processes?
$(i) \, Cl$ $\xrightarrow{E.A.} Cl^{-} \, \, \, \, \, (ii) \, Cl^{-}$ $\xrightarrow{I.E.} Cl \, \, \, (iii) \, \, Cl$ $\xrightarrow{I.E.} Cl^{+} \, \, \, (iv) \, \, Cl^{+}$ $\xrightarrow{I.E.} Cl^{2+}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module