Which of the following order is incorrect?

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(C) Let us analyze each option:$A$: Electronegativity of the central atom depends on its oxidation state and hybridization. In $CF_4$,$C$ is $sp^3$ hy

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Electrical conductance : $F^{-}_{(aq.)} > Cl^{-}_{(aq.)} > S^{2-}_{(aq.)}$

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(C) Let us analyze each option:$A$: Electronegativity of the central atom depends on its oxidation state and hybridization. In $CF_4$,$C$ is $sp^3$ hybridized and bonded to highly electronegative $F$. In $CH_4$,$C$ is $sp^3$ hybridized. In $SiH_4$,$Si$ is less electronegative than $C$. The order $CF_4 > CH_4 > SiH_4$ is correct.$B$: Hydration energy is directly proportional to charge density $(charge/size)$. $Al^{3+}$ $(3+/small)$ > $Be^{2+}$ $(2+/small)$ > $Mg^{2+}$ $(2+/larger)$ > $Na^{+}$ $(1+/larger)$. This order is correct.$C$: Electrical conductance in aqueous solution depends on ionic mobility. Smaller ions with higher charge density are more heavily hydrated,making them larger and slower. $S^{2-}$ has a larger size and lower charge density compared to $F^{-}$ and $Cl^{-}$,thus it has higher mobility. The given order $F^{-} > Cl^{-} > S^{2-}$ is incorrect.$D$: Magnetic moment $\mu = \sqrt{n(n+2)} \ BM$. $Ni^{4+}$ ($3d^6$,$n=4$),$V^{3+}$ ($3d^2$,$n=2$),$Sr^{2+}$ ($[Kr]$,$n=0$). The order $Ni^{4+} > V^{3+} > Sr^{2+}$ is correct.

List-$I$ (Classification of molecules based on octet rule)	List-$II$ (Example)
$A$. Molecules obeying octet rule	$I$. $NO, NO_2$
$B$. Molecules with incomplete octet	$II$. $BCl_3, AlCl_3$
$C$. Molecules with odd electron	$III$. $H_2SO_4, PCl_5$
$D$. Molecules with expanded octet	$IV$. $CCl_4, CO_2$

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