Which of the following orders is incorrect?

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(A) The number of protons in $H$,$D$,and $T$ is the same ($1$ proton each). Therefore,the number of protons in $H_2$,$D_2$,and $T_2$ is equal ($2$ pro

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$H_2 < D_2 < T_2$ (Number of protons)

Vedclass · Answer

(A) The number of protons in $H$,$D$,and $T$ is the same ($1$ proton each). Therefore,the number of protons in $H_2$,$D_2$,and $T_2$ is equal ($2$ protons each). The order $H_2 Bond energy increases with the mass of the isotope due to the decrease in zero-point energy,so $H_2 Boiling point increases with molecular mass and van der Waals forces,so $H_2 The number of neutrons in $H$,$D$,and $T$ is $0$,$1$,and $2$ respectively. Thus,the number of neutrons in $H_2$,$D_2$,and $T_2$ is $0$,$2$,and $4$ respectively,making $H_2 < D_2 < T_2$ correct.

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