Which of the following orders regarding relative stability of free radicals is correct?
- A$3^\circ < 2^\circ < 1^\circ$
- B$3^\circ > 2^\circ > 1^\circ$
- C$1^\circ < 2^\circ > 3^\circ$
- D$3^\circ > 2^\circ < 1^\circ$
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Similar Questions
Which is the correct order of stability of the following three carbonium ions?
$(I)$ $CH_2 = CH - CH^+ - CH_3$
$(II)$ $CH_2 = C(CH_3) - CH_2^+$
$(III)$ $CH_3 - CH = CH - CH_2^+$
$(I)$ $CH_2 = CH - CH^+ - CH_3$
$(II)$ $CH_2 = C(CH_3) - CH_2^+$
$(III)$ $CH_3 - CH = CH - CH_2^+$
DifficultAIIMS 2014
View SolutionAmong the following, which is the most stable carbocation?
What is the order of stability of the following carbocations?
$(X). CH_3 - \overset{\oplus}{C}H - CH_3$
$(Y). CH_3 - \overset{\oplus}{C}H - OCH_3$
$(Z). CH_3 - \overset{\oplus}{C}H - COCH_3$
$(X). CH_3 - \overset{\oplus}{C}H - CH_3$
$(Y). CH_3 - \overset{\oplus}{C}H - OCH_3$
$(Z). CH_3 - \overset{\oplus}{C}H - COCH_3$
Medium
View SolutionConsider the following carbocations. What is the relative stability order of these carbocations?
$(1)$ $CH_3O-C_6H_4-CH_2^+$
$(2)$ $C_6H_5-CH_2^+$
$(3)$ $CH_3-C_6H_4-CH_2^+$
$(1)$ $CH_3O-C_6H_4-CH_2^+$
$(2)$ $C_6H_5-CH_2^+$
$(3)$ $CH_3-C_6H_4-CH_2^+$
Medium
View SolutionThe central carbon atom of a free radical contains
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