Which of the following oxyacids of chlorine d | vedclass

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(C) To determine the number of lone pairs on the chlorine atom,we examine the oxidation state and bonding of chlorine in each oxyacid:$1$. $HOCl$ $(HC

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$HOClO_{3}$

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(C) To determine the number of lone pairs on the chlorine atom,we examine the oxidation state and bonding of chlorine in each oxyacid:$1$. $HOCl$ $(HClO)$: Chlorine is in the $+1$ oxidation state. It forms $1$ single bond with $O$ and has $3$ lone pairs.$2$. $HOClO$ $(HClO_{2})$: Chlorine is in the $+3$ oxidation state. It forms $1$ single bond with $OH$ and $1$ double bond with $O$,leaving $2$ lone pairs.$3$. $HOClO_{2}$ $(HClO_{3})$: Chlorine is in the $+5$ oxidation state. It forms $1$ single bond with $OH$ and $2$ double bonds with $O$,leaving $1$ lone pair.$4$. $HOClO_{3}$ $(HClO_{4})$: Chlorine is in the $+7$ oxidation state. It forms $1$ single bond with $OH$ and $3$ double bonds with $O$. Since chlorine has $7$ valence electrons and all are involved in bonding,there are $0$ lone pairs on the chlorine atom.Therefore,$HOClO_{3}$ is the correct answer.

Which of the following oxyacids of chlorine does not contain a lone pair of electrons on the chlorine atom?

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