Which of the following pairs are not logicall | vedclass

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(B) We evaluate each pair for logical equivalence:$A$. $\sim (\sim p) \equiv p$ (Law of Double Negation). These are equivalent.$B$. $p \vee (p \wedge

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$p \vee (p \wedge q)$ and $q$

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(B) We evaluate each pair for logical equivalence:$A$. $\sim (\sim p) \equiv p$ (Law of Double Negation). These are equivalent.$B$. $p \vee (p \wedge q) \equiv p$ (Absorption Law). Since $p 
ot\equiv q$,these are not logically equivalent.$C$. $\sim (p \wedge q) \equiv \sim p \vee \sim q$ (De Morgan's Law). These are equivalent.$D$. $\sim (\sim p \wedge q) \equiv \sim (\sim p) \vee \sim q \equiv p \vee \sim q$ (De Morgan's Law). These are equivalent.Thus,the pair in option $B$ is not logically equivalent.

Which of the following pairs are not logically equivalent?

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