(C) The correct answer is $C$. In ethylene $(CH_2=CH_2)$,the carbon atoms are $sp^2$ hybridized,resulting in a bond angle of $120^{\circ}$. In benzene

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(C) The correct answer is $C$. In ethylene $(CH_2=CH_2)$,the carbon atoms are $sp^2$ hybridized,resulting in a bond angle of $120^{\circ}$. In benzene $(C_6H_6)$,each carbon atom is also $sp^2$ hybridized,resulting in a bond angle of $120^{\circ}$. Therefore,both ethylene and benzene have the same bond angle of $120^{\circ}$.

Class 11 Chemistry Chemical Bonding and Molecular Structure Hybridisation

Medium

Which of the following pairs has the same bond angle?

A
Ethane and ethylene
B
Ethylene and acetylene
C
Ethylene and benzene
D
Acetylene and benzene

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Class 11

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Chapter

Chemical Bonding and Molecular Structure

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Hybridisation

The $H-O-H$ bond angles in $H_3O^+$ are approximately $107^\circ$. The orbitals used by oxygen in these bonds are best described as

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The hybridizations of atomic orbitals of nitrogen in $NO_2^+$,$NO_3^-$ and $NH_4^+$ respectively are

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In the acetylene molecule,the $C-H$ sigma bond is formed by the overlap of which orbitals?

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Among the compounds,$BF_3$,$NCl_3$,$H_2S$,$SF_4$ and $BeCl_2$,identify the ones in which the central atom has the same type of hybridization.

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The central atom in a molecule is in $sp^2$ hybrid state. The shape of the molecule will be

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Which of the following pairs has the same bond angle?

Similar Questions

The $H-O-H$ bond angles in $H_3O^+$ are approximately $107^\circ$. The orbitals used by oxygen in these bonds are best described as

The hybridizations of atomic orbitals of nitrogen in $NO_2^+$,$NO_3^-$ and $NH_4^+$ respectively are

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