Which of the following paramagnetic ions woul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic moment (spin only) is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For

Vedclass · Accepted Answer

$Cr^{2+}$

Vedclass · Answer

(D) The magnetic moment (spin only) is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$1$. For $Mn^{2+}$ $(d^5)$: $n = 5$,$\mu = \sqrt{5(5+2)} = \sqrt{35} \approx 5.92 \ BM$.$2$. For $Ti^{2+}$ $(d^2)$: $n = 2$,$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.83 \ BM$.$3$. For $V^{2+}$ $(d^3)$: $n = 3$,$\mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \ BM$.$4$. For $Cr^{2+}$ $(d^4)$: $n = 4$,$\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 \ BM$.The value $4.90 \ BM$ is of the order of $5 \ BM$. Thus,$Cr^{2+}$ is the correct answer.

Which of the following paramagnetic ions would exhibit a magnetic moment (spin only) of the order of $5 \ BM$?
(At. Nos. $Mn = 25$,$Cr = 24$,$V = 23$,$Ti = 22$)

Similar Questions

Which of the following options represents the increasing order of the paramagnetic property of the ions?

Invar,an alloy of $Fe$ and $Ni$,is used in watches and meter scales. Its characteristic property is:

Consider the hydrated ions of $Ti^{2+}$,$V^{2+}$,$Ti^{3+}$,and $Sc^{3+}$. The correct order of their spin-only magnetic moments is

Variable valency,in general,is exhibited by

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which of the following paramagnetic ions would exhibit a magnetic moment (spin only) of the order of $5 \ BM$?(At. Nos. $Mn = 25$,$Cr = 24$,$V = 23$,$Ti = 22$)