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(A) The transformation involves the reduction of acetophenone $(C_6H_5COCH_3)$ to a secondary alcohol where a deuterium atom is incorporated at the al

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$NaBD_4$ in $CH_3OH$

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(A) The transformation involves the reduction of acetophenone $(C_6H_5COCH_3)$ to a secondary alcohol where a deuterium atom is incorporated at the alpha-carbon position.$NaBD_4$ acts as a source of deuteride ions $(D^-)$.When $NaBD_4$ reacts with the ketone in a protic solvent like $CH_3OH$,the $D^-$ ion attacks the carbonyl carbon to form a $C-D$ bond,and the oxygen is protonated by the solvent to form an $-OH$ group.Therefore,$NaBD_4$ in $CH_3OH$ will yield the product $C_6H_5CH(D)OH$.

Which of the following reagents would carry out the following transformation?
$C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).

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Which of the following reagents would carry out the following transformation? $C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).