Which of the following relations about E^{cir | vedclass

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(D) The standard cell potential is given by $E^{\circ}_{cell} = E^{\circ}_{cathode} - E^{\circ}_{anode}$.From the Nernst equation at equilibrium,$\Del

Vedclass · Accepted Answer

$E^{\circ}_{cell} = E^{\circ}_{anode} + E^{\circ}_{cathode}$

Vedclass · Answer

(D) The standard cell potential is given by $E^{\circ}_{cell} = E^{\circ}_{cathode} - E^{\circ}_{anode}$.From the Nernst equation at equilibrium,$\Delta G^{\circ} = -nFE^{\circ}_{cell}$,which implies $E^{\circ}_{cell} = \frac{-\Delta G^{\circ}}{nF}$.Also,$E^{\circ}_{cell} = \frac{RT}{nF} \ln K_{c} = \frac{0.0592}{n} \log_{10} K_{c}$ at $298 \ K$.Option $D$ is false because the standard cell potential is the difference between the reduction potentials of the cathode and the anode,not the sum.

Which of the following relations about $E^{\circ}_{cell}$ is false?

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