Which of the following sets of quantum numbers is possible?

  • A
    $n = 4, l = 3, m = -2, s = 0$
  • B
    $n = 4, l = 4, m = +2, s = -\frac{1}{2}$
  • C
    $n = 4, l = 4, m = -2, s = +\frac{1}{2}$
  • D
    $n = 4, l = 3, m = -2, s = +\frac{1}{2}$

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An electron having the quantum numbers $n = 4, l = 3, m = 0, s = -\frac{1}{2}$ would be in the orbital

Match List-$I$ with List-$II$ :
List-$I$ (Quantum number)List-$II$ (Orbital)
$a. n=2, \ell=1$$i. 2s$
$b. n=3, \ell=2$$ii. 3s$
$c. n=3, \ell=0$$iii. 2p$
$d. n=2, \ell=0$$iv. 3d$

Choose the correct answer from the options given below :

Compare the energies of the following sets of quantum numbers for a multielectron system:
$A. n=4, \ell=1$
$B. n=4, \ell=2$
$C. n=3, \ell=1$
$D. n=3, \ell=2$
$E. n=4, \ell=0$
Choose the correct answer from the options given below:

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