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(C) The freezing point depression is given by the formula $\Delta T_f = i 	imes K_f 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molal

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$1 \ m \ AlPO_4$

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(C) The freezing point depression is given by the formula $\Delta T_f = i 	imes K_f 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molality. For $0.1 \ m \ NaCl$,$i = 2$,so $\Delta T_f = 2 	imes 0.1 = 0.2$. For $0.05 \ m \ MgSO_4$,$i = 2$,so $\Delta T_f = 2 	imes 0.05 = 0.1$. For $1 \ m \ AlPO_4$,$i = 2$,so $\Delta T_f = 2 	imes 1 = 2.0$. For $0.05 \ m \ Al_2(SO_4)_3$,$i = 5$,so $\Delta T_f = 5 	imes 0.05 = 0.25$. Comparing the values,$1 \ m \ AlPO_4$ has the highest value of $i 	imes m$,therefore it exhibits the highest freezing point depression.

Which of the following solutions exhibits the highest freezing point depression?

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