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(D) The boiling point elevation is given by the formula $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molalit

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$0.05 \ m \ MgCl_2$

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(D) The boiling point elevation is given by the formula $\Delta T_b = i 	imes K_b 	imes m$,where $i$ is the van't Hoff factor and $m$ is the molality. Since $K_b$ is constant,$\Delta T_b$ is proportional to $i 	imes m$. For complete dissociation,$i$ equals the number of ions produced per formula unit. $A$: $KCl ightarrow K^+ + Cl^-$,$i = 2$. $\Delta T_b \propto 2 	imes 0.2 = 0.4$. $B$: $NaCl ightarrow Na^+ + Cl^-$,$i = 2$. $\Delta T_b \propto 2 	imes 0.1 = 0.2$. $C$: $AlCl_3 ightarrow Al^{3+} + 3Cl^-$,$i = 4$. $\Delta T_b \propto 4 	imes 1 = 4.0$. $D$: $MgCl_2 ightarrow Mg^{2+} + 2Cl^-$,$i = 3$. $\Delta T_b \propto 3 	imes 0.05 = 0.15$. Comparing the values,$0.15 < 0.2 < 0.4 < 4.0$. Thus,$0.05 \ m \ MgCl_2$ exhibits the minimum boiling point elevation.

Which of the following solutions exhibits the minimum boiling point elevation under identical conditions? (Assume complete dissociation)

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