Which of the following statement(s) is(are) c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For $(A)$: For the Balmer series,transitions occur to $n=2$. The longest wavelength corresponds to $n=3 	o n=2$,and the shortest to $n=\infty 	o

Vedclass · Accepted Answer

$A, C$

Vedclass · Answer

(B) For $(A)$: For the Balmer series,transitions occur to $n=2$. The longest wavelength corresponds to $n=3 	o n=2$,and the shortest to $n=\infty 	o n=2$.$\frac{1}{\lambda_{\max}} = R(\frac{1}{2^2} - \frac{1}{3^2}) = R(\frac{5}{36}) \Rightarrow \lambda_{\max} = \frac{36}{5R}$.$\frac{1}{\lambda_{\min}} = R(\frac{1}{2^2} - 0) = \frac{R}{4} \Rightarrow \lambda_{\min} = \frac{4}{R}$.Ratio $\frac{\lambda_{\max}}{\lambda_{\min}} = \frac{36/5R}{4/R} = \frac{9}{5}$. Statement $(A)$ is correct.For $(B)$: Balmer range is $[364.6 \ nm, 656.3 \ nm]$. Paschen range is $[820.4 \ nm, 1875.1 \ nm]$. They do not overlap. Statement $(B)$ is incorrect.For $(C)$: For Lyman series,$\frac{1}{\lambda} = R(1 - \frac{1}{m^2})$ where $m=2, 3, \dots$. Since $\frac{1}{\lambda_0} = R$,we have $\frac{1}{\lambda} = \frac{1}{\lambda_0}(1 - \frac{1}{m^2}) \Rightarrow \lambda = \frac{\lambda_0}{1 - 1/m^2}$. Statement $(C)$ is correct.For $(D)$: Lyman range is $[91.2 \ nm, 121.6 \ nm]$. Balmer range is $[364.6 \ nm, 656.3 \ nm]$. They do not overlap. Statement $(D)$ is correct.

Similar Questions

In the spectrum of hydrogen,the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is

The transition of an electron in a hydrogen atom that emits a photon whose wavelength lies in the ultraviolet region of the electromagnetic spectrum is

The number of possible spectral lines in a hydrogen atom is:

Which of the following spectral series of the hydrogen atom lies entirely in the ultraviolet region?

The ratio of the shortest wavelengths of Bracket and Balmer series of hydrogen atom is

Vedclass Test Series

Exam Paper Generator

Online Exam Module