Which of the following statements is true?

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(B) For an elastic collision between two bodies of masses $m_{1}$ and $m_{2}$,the law of conservation of momentum states:$m_{1} u_{1} + m_{2} u_{2} =

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By definition,there is no difference between elastic and perfectly elastic collisions.

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(B) For an elastic collision between two bodies of masses $m_{1}$ and $m_{2}$,the law of conservation of momentum states:$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$$m_{1}(u_{1} - v_{1}) = m_{2}(v_{2} - u_{2})$ $...(i)$The law of conservation of kinetic energy $(KE)$ states:$\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2} = \frac{1}{2} m_{1} v_{1}^{2} + \frac{1}{2} m_{2} v_{2}^{2}$$m_{1}(u_{1}^{2} - v_{1}^{2}) = m_{2}(v_{2}^{2} - u_{2}^{2})$ $...(ii)$Dividing equation $(ii)$ by equation $(i)$:$u_{1} + v_{1} = v_{2} + u_{2}$$(u_{1} - u_{2}) = (v_{2} - v_{1})$$\frac{v_{2} - v_{1}}{u_{1} - u_{2}} = 1$This ratio is the coefficient of restitution $e$. For a perfectly elastic collision,$e = 1$. By definition,the terms 'elastic' and 'perfectly elastic' refer to the same physical process where both momentum and kinetic energy are conserved.

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