Which of the following statements is wrong?

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Question

(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is

Vedclass · Accepted Answer

Infrared photon has more energy than the photon of visible light

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength.From this relation,we see that $E \propto \frac{1}{\lambda}$,meaning energy is inversely proportional to wavelength.Infrared radiation has a longer wavelength than visible light. Therefore,infrared photons have less energy than visible light photons.Statement $A$ claims that infrared photons have more energy than visible light,which is incorrect.Photographic plates can be made sensitive to both ultraviolet and infrared rays,making statements $B$ and $C$ correct.Infrared rays,like visible light,travel in straight lines and are blocked by opaque objects,thus they can cast shadows,making statement $D$ correct.

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