Which of the following statement$(s)$ is/are correct? [$T$ for True and $F$ for False$]$
$(a)$ Hybrid orbitals form stronger bonds than pure atomic orbitals.
$(b)$ Canonical structures have a difference in the arrangement of atoms $w.r.t.$ each other.
$(c)$ Any symmetrical molecule always contains the same bond angle.
$(d)$ $VSEPR$ theory can explain the square planar geometry of $XeF_4$.

The correct order as indicated in each option is

Which of the following statements is true with respect to $H_2O$,$NH_3$ and $CH_4$?
$A.$ The central atoms of all the molecules are $sp^3$ hybridized.
$B.$ The $H-O-H$,$H-N-H$ and $H-C-H$ angles in the above molecules are $104.5^{\circ}$,$107.5^{\circ}$ and $109.5^{\circ}$ respectively.
$C.$ The increasing order of dipole moment is $CH_4 < NH_3 < H_2O$.
$D.$ Both $H_2O$ and $NH_3$ are Lewis acids and $CH_4$ is a Lewis base.
$E.$ $A$ solution of $NH_3$ in $H_2O$ is basic. In this solution,$NH_3$ and $H_2O$ act as a Lowry-Bronsted base and acid respectively.
Choose the correct answer from the options given below:

Which of these represents the incorrect order of the mentioned property?

What is true about $S_8$ molecule?
$I.$ There are no $p_{\pi}-p_{\pi}$ bonds present in the molecule.
$II.$ There are eight lone pairs of electrons.
$III.$ Each $S$ atom is $sp^3$ hybridized.

What is the number of electrons around sulfur in $H_2SO_4$ molecule?