Which of the following statements are correct | vedclass

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(A) $(I)$ In a nitrating mixture $(HNO_3 + H_2SO_4)$,$HNO_3$ acts as a base because it accepts a proton from $H_2SO_4$ to form the nitronium ion $(NO_

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$II, III$ only

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(A) $(I)$ In a nitrating mixture $(HNO_3 + H_2SO_4)$,$HNO_3$ acts as a base because it accepts a proton from $H_2SO_4$ to form the nitronium ion $(NO_2^+)$. Thus,statement $I$ is incorrect.$(II)$ The $\sigma$-complex (arenium ion) is the intermediate formed during the electrophilic aromatic substitution of benzene when an electrophile $(E^+)$ attacks the benzene ring. In this complex,one carbon atom becomes $sp^3$-hybridized. Thus,statement $II$ is correct.$(III)$ During the Friedel-Crafts alkylation of benzene with $n$-propyl chloride,the primary carbocation $(CH_3CH_2CH_2^+)$ rearranges to a more stable secondary carbocation $(CH_3CH^+CH_3)$. Consequently,the major product formed is isopropyl benzene. Thus,statement $III$ is correct.Therefore,statements $II$ and $III$ are correct,making option $(A)$ the correct answer.

Which of the following statements are correct?
$I$. In nitrating mixture,nitric acid participates as an acid.
$II$. $\sigma$-complex is the intermediate substance in electrophilic substitution of benzene.
$III$. Benzene on Friedel-Crafts alkylation with $n$-propyl chloride gives isopropyl benzene.

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Which of the following statements are correct?$I$. In nitrating mixture,nitric acid participates as an acid.$II$. $\sigma$-complex is the intermediate substance in electrophilic substitution of benzene.$III$. Benzene on Friedel-Crafts alkylation with $n$-propyl chloride gives isopropyl benzene.