Which of the following substances consists of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For $4.25 \ g$ of $NH_3$: Moles of $NH_3 = \frac{4.25 \ g}{17 \ g/mol} = 0.25 \ mol$. Total atoms $= 0.25 \ mol 	imes (1 + 3) \ atoms/molecule =

Vedclass · Accepted Answer

$4.25 \ g$ of $NH_3$

Vedclass · Answer

(A) For $4.25 \ g$ of $NH_3$: Moles of $NH_3 = \frac{4.25 \ g}{17 \ g/mol} = 0.25 \ mol$. Total atoms $= 0.25 \ mol 	imes (1 + 3) \ atoms/molecule = 1 \ mol$ of atoms.For $1.8 \ g$ of $H_2O$: Moles of $H_2O = \frac{1.8 \ g}{18 \ g/mol} = 0.1 \ mol$. Total atoms $= 0.1 \ mol 	imes (2 + 1) = 0.3 \ mol$ of atoms.For $2.8 \ g$ of $N_2$: Moles of $N_2 = \frac{2.8 \ g}{28 \ g/mol} = 0.1 \ mol$. Total atoms $= 0.1 \ mol 	imes 2 = 0.2 \ mol$ of atoms.For $4.4 \ g$ of $CO_2$: Moles of $CO_2 = \frac{4.4 \ g}{44 \ g/mol} = 0.1 \ mol$. Total atoms $= 0.1 \ mol 	imes (1 + 2) = 0.3 \ mol$ of atoms.Thus,$4.25 \ g$ of $NH_3$ contains $1 \ mol$ of atoms.

Which of the following substances consists of a total of $1 \ mol$ of atoms? (Molar mass of $NH_3 = 17 \ g/mol, H_2O = 18 \ g/mol, N_2 = 28 \ g/mol, CO_2 = 44 \ g/mol$)

Similar Questions

If one atom of an element $X$ weighs $6.643 \times 10^{-23} \ g$,then find the number of moles of atoms in $50 \ kg$ of element $X$. (in $moles$)

What is the number of atoms in $280 \ g$ of $Fe$?

If every person on Earth is given $100$ molecules of sugar,how much sugar $(C_{12}H_{22}O_{11})$ is required? (Assume the population of Earth is $3 \times 10^{10}$ and the molar mass of sugar is $342 \ g/mol$)

What is the number of moles of $N$ atoms and number of moles of $O$ atoms respectively present in one mole of uracil?

What is the approximate weight of one molecule of methane $(CH_4)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module