Which of the following tetracarboxylic acids | vedclass

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a

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Both $(a)$ and $(b)$

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a di-anhydride,it must have two pairs of adjacent carboxylic acid groups. In benzene$-1,2,3,4-$tetracarboxylic acid,there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $3,4$),allowing for the formation of a di-anhydride. In benzene$-1,2,4,5-$tetracarboxylic acid (pyromellitic acid),there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $4,5$),which also allows for the formation of a di-anhydride. Therefore,both compounds can form di-anhydrides upon heating.

List-$I$	List-$II$
$(a)$ $R-COCl \to R-CHO$	$(i)$ $Br_2 / NaOH$
$(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$	$(ii)$ $H_2 / Pd-BaSO_4$
$(c)$ $R-CONH_2 \to R-NH_2$	$(iii)$ $Zn(Hg) / \text{Conc. } HCl$
$(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$	$(iv)$ $Cl_2 / \text{Red } P, H_2O$

Which of the following tetracarboxylic acids forms a di-anhydride upon heating?

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