Which of the following will have maximum stab | vedclass

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(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong

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$[Co(CN)_6]^{3-}$

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(C) The crystal field stabilization energy $(CFSE)$ depends on the nature of the ligand and the oxidation state of the metal ion.
$CN^-$ is a strong field ligand,which causes a large splitting of $d$-orbitals $(\Delta_o)$.
In $[Co(CN)_6]^{3-}$,$Co$ is in the $+3$ oxidation state ($d^6$ configuration).
Since $CN^-$ is a strong field ligand,it leads to a low-spin $t_{2g}^6 e_g^0$ configuration,resulting in a very high $CFSE$ value compared to the other complexes listed,which involve weak field ligands like $H_2O$ or have lower oxidation states.

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

Which of the following will have maximum stabilization due to crystal field?

Similar Questions

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

The degenerate orbitals of $[Cr(H_2O)_6]^{3+}$ are

Among the following complexes,the one which shows zero crystal field stabilization energy $(CFSE)$ is

Why do transition elements form coloured compounds?

In which of the following complexes of the $Co$ (at. no. $27$),will the magnitude of $\Delta_o$ be the highest?

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