Which of the two stereoisomers of 4-t-butylcy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In isomer $A$,the iodine atom is in the axial position. Due to $1,3-$diaxial interactions,the leaving group $(I^-)$ is more sterically crowded and

Vedclass · Accepted Answer

$A$ will react faster because the approach of $^{128}I^-$ can occur unhindered.

Vedclass · Answer

(C) In isomer $A$,the iodine atom is in the axial position. Due to $1,3-$diaxial interactions,the leaving group $(I^-)$ is more sterically crowded and experiences repulsion,which facilitates its departure.In isomer $B$,the iodine atom is in the equatorial position,which is less sterically hindered and more stable,making the departure of the leaving group slower.Therefore,the axial isomer $(A)$ undergoes $S_N2$ substitution faster due to the relief of steric strain upon the departure of the leaving group.

Which of the two stereoisomers of $4-t-$butylcyclohexyl iodide $(^{127}I^-)$ will undergo $S_N2$ substitution with $^{128}I^-$ faster,and why?

Similar Questions

Identify the correct statement for the below given transformation:
$CH_{3}CH_{2}CH_{2}CH(N^{+}(CH_{3})_{3})CH_{3}$ $\xrightarrow{C_{2}H_{5}ONa / C_{2}H_{5}OH} A (\text{major}) + B (\text{minor})$

In which case is the formation of $butanenitrile$ possible?

Among the given halides,which one will give the same product in both $S_{N^1}$ and $S_{N^2}$ reactions?
$(I) \ CH_3-CH(CH_3)-CH_2-CH(Br)-CH_3$
$(II) \ \text{2-methylcyclohexyl chloride}$
$(III) \ \text{Chlorocyclohexane}$
$(IV) \ CH_3-CH(Br)-CH_2-CH_3$

The formation of butane nitrile is possible in which of the following reactions?

The major product $P$ of the above reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module