Which one has the highest paramagnetism?

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Question

(C) Paramagnetism is directly proportional to the number of unpaired electrons $(n)$.$1$. In $Ni(CO)_4$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$.

Vedclass · Accepted Answer

$[Ni(NH_3)_6]Cl_2$

Vedclass · Answer

(C) Paramagnetism is directly proportional to the number of unpaired electrons $(n)$.$1$. In $Ni(CO)_4$,$Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons,so $n = 0$.$2$. In $[Ni(NH_3)_4]Cl_2$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $NH_3$ is a strong field ligand,causing pairing,so $n = 0$ (square planar).$3$. In $[Ni(NH_3)_6]Cl_2$,$Ni$ is in $+2$ oxidation state $(3d^8)$. $NH_3$ is a strong field ligand,but in octahedral geometry,$n = 2$.$4$. In $[Cu(NH_3)_4]Cl_2$,$Cu$ is in $+2$ oxidation state $(3d^9)$. There is $1$ unpaired electron,so $n = 1$.Comparing the values,$[Ni(NH_3)_6]Cl_2$ has the highest number of unpaired electrons $(n = 2)$,hence it shows the highest paramagnetism.

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