Which one is stronger,$\sigma$ bond or $\pi$ bond? Why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The $\sigma$ bond is stronger than the $\pi$ bond.
The strength of a covalent bond depends on the extent of overlapping of atomic orbitals.
In the formation of a $\sigma$ bond,the atomic orbitals overlap along the internuclear axis (head-on overlap),which results in a greater extent of overlapping.
In the formation of a $\pi$ bond,the atomic orbitals overlap sideways (lateral overlap),which results in a smaller extent of overlapping.
Since the strength of a bond is directly proportional to the magnitude of overlapping,the $\sigma$ bond is stronger than the $\pi$ bond.

Explore More

Similar Questions

Which of the following represent zero overlap (non-bonding condition)?

Determine the number of $\sigma$ and $\pi$ bonds in the following molecules:
$(i)$ $O_2$
$(ii)$ $N_2$
$(iii)$ $C_6H_6$ (Benzene)
$(iv)$ $O_3$ (Ozone)

In a diatomic molecule,the internuclear axis is $Z$. Which of the following bonds will be formed by the overlap of $P_x$ and $P_y$ orbitals?

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: Zero orbital overlap is an out-of-phase overlap.
Reason $R$: It results due to different orientation/direction of approach of orbitals.
In the light of the above statements,choose the correct answer from the options given below.

The $p-p$ orbital overlapping is present in the following molecule:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo