Which one is the correct order of the size of | vedclass

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(D) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For the same element,the size order is $I^{-} > I

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$I^{-} > I > I^{+}$

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(D) The size of an atom or ion depends on the number of electrons and the effective nuclear charge. For the same element,the size order is $I^{-} > I > I^{+}$. $I^{-}$ has $54$ electrons,$I$ has $53$ electrons,and $I^{+}$ has $52$ electrons. As the number of electrons decreases for the same nuclear charge,the effective nuclear charge per electron increases,leading to a smaller size. Therefore,the correct order is $I^{-} > I > I^{+}$.

Which one is the correct order of the size of the iodine species?

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