Which one of the following alkenes when treat | vedclass

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(B) The reaction of $HCl$ with an alkene typically follows Markovnikov's rule,where the proton adds to the carbon with more hydrogen atoms to form the

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$F_3C-CH=CH_2$

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(B) The reaction of $HCl$ with an alkene typically follows Markovnikov's rule,where the proton adds to the carbon with more hydrogen atoms to form the more stable carbocation.However,if an electron-withdrawing group $(EWG)$ like $-CF_3$ is attached to the double bond,it destabilizes the carbocation formed at the adjacent carbon.In the case of $F_3C-CH=CH_2$,the formation of a carbocation at the carbon attached to the $-CF_3$ group $(F_3C-CH^+-CH_3)$ is highly unstable due to the strong inductive effect of the three fluorine atoms.Therefore,the proton adds to the carbon attached to the $-CF_3$ group,leading to the formation of the more stable carbocation at the terminal carbon $(F_3C-CH_2-CH_2^+)$.Subsequent attack by the chloride ion $(Cl^-)$ results in the anti-Markovnikov product,$F_3C-CH_2-CH_2Cl$.

Which one of the following alkenes when treated with $HCl$ yields majorly an anti-Markovnikov product?

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