Which one of the following compounds is not c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The colour of transition metal complexes is generally due to $d-d$ transitions,which require the presence of unpaired $d$-electrons. In $Na_2CdCl_

Vedclass · Accepted Answer

$Na_2CdCl_4$

Vedclass · Answer

(B) The colour of transition metal complexes is generally due to $d-d$ transitions,which require the presence of unpaired $d$-electrons. In $Na_2CdCl_4$,the cadmium ion is $Cd^{2+}$. The electronic configuration of $Cd$ $(Z=48)$ is $[Kr] 4d^{10} 5s^2$. Thus,$Cd^{2+}$ has the configuration $[Kr] 4d^{10}$. Since the $d$-subshell is completely filled,there are no unpaired electrons available for $d-d$ transitions,making the compound colourless. Therefore,the correct option is $(B)$.

Which one of the following compounds is not coloured?

Similar Questions

How many geometrical isomers and stereoisomers are possible for $[Pt(NO_2)(NH_3)(NH_2OH)(Py)]^+$ and $[Pt(Br)(Cl)(I)(NO_2)(NH_3)(Py)]$ respectively?

Select the correct code regarding the total number of stereoisomers for the following compounds:
$I. [Ma_3b_2c]^{n \pm}, II. [M(AB)_3]^{n \pm}, III. [Ma_2b_2c_2]^{n \pm}$
$I - II - III$

Which type of isomerism is exhibited by the isomers $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$?

Which of the following will exhibit optical activity?

The number of geometric isomers that can exist for the square planar complex $[Pt(Cl)(py)(NH_3)(NH_2OH)]^+$ is ($py=$ pyridine):

Vedclass Test Series

Exam Paper Generator

Online Exam Module