Which one of the following compounds will lib | vedclass

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(B) Compounds that are more acidic than $H_{2}CO_{3}$ (carbonic acid) will react with $NaHCO_{3}$ to liberate $CO_{2}$.$(CH_{3})_{3}NH^{+}Cl^{-}$ is a

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$(CH_{3})_{3}NH^{+}Cl^{-}$

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(B) Compounds that are more acidic than $H_{2}CO_{3}$ (carbonic acid) will react with $NaHCO_{3}$ to liberate $CO_{2}$.$(CH_{3})_{3}NH^{+}Cl^{-}$ is a salt of a weak base and a strong acid,making the cation $(CH_{3})_{3}NH^{+}$ acidic enough to react with $HCO_{3}^{-}$:$(CH_{3})_{3}NH^{+}Cl^{-} + NaHCO_{3} \longrightarrow (CH_{3})_{3}N + NaCl + H_{2}CO_{3}$$H_{2}CO_{3} \longrightarrow H_{2}O + CO_{2} \uparrow$Therefore,option $B$ is the correct answer.

Which one of the following compounds will liberate $CO_{2}$ when treated with $NaHCO_{3}$?

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