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(B) The van't Hoff factor $(i)$ for a $100 \%$ ionised electrolyte is equal to the total number of ions produced per formula unit.For $Al_2(SO_4)_3$:

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$K_4[Fe(CN)_6]$

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(B) The van't Hoff factor $(i)$ for a $100 \%$ ionised electrolyte is equal to the total number of ions produced per formula unit.For $Al_2(SO_4)_3$: $Al_2(SO_4)_3 \rightarrow 2 Al^{3+} + 3 SO_4^{2-}$. Total ions = $2 + 3 = 5$,so $i = 5$.For $Al(NO_3)_3$: $Al(NO_3)_3 \rightarrow Al^{3+} + 3 NO_3^-$. Total ions = $1 + 3 = 4$,so $i = 4$.For $K_4[Fe(CN)_6]$: $K_4[Fe(CN)_6] \rightarrow 4 K^{+} + [Fe(CN)_6]^{4-}$. Total ions = $4 + 1 = 5$,so $i = 5$.For $K_2SO_4$: $K_2SO_4 \rightarrow 2 K^{+} + SO_4^{2-}$. Total ions = $2 + 1 = 3$,so $i = 3$.For $K_3[Fe(CN)_6]$: $K_3[Fe(CN)_6] \rightarrow 3 K^{+} + [Fe(CN)_6]^{3-}$. Total ions = $3 + 1 = 4$,so $i = 4$.Thus,$K_4[Fe(CN)_6]$ has the same van't Hoff factor as $Al_2(SO_4)_3$.

Which one of the following electrolytes has the same value of van't Hoff factor $(i)$ as that of $Al_2(SO_4)_3$ (if all are $100 \%$ ionised)?

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