Which one of the following electronic arrangements is absurd?

  • A
    $n=3, l=1, m=-1$
  • B
    $n=3, l=0, m=0$
  • C
    $n=2, l=0, m=-1$
  • D
    $n=2, l=1, m=0$

Explore More

Similar Questions

Define the principal quantum number $(n)$.

Two electrons occupying the same orbital are distinguished by

The azimuthal quantum number for the valence electrons of $Ga^{+}$ ion is $.....$
(Atomic number of $Ga = 31$)

Using $s$,$p$,$d$,and $f$ notations,describe the orbital with the following quantum numbers:
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$

Compare the energies of the following sets of quantum numbers for a multielectron system:
$A. n=4, \ell=1$
$B. n=4, \ell=2$
$C. n=3, \ell=1$
$D. n=3, \ell=2$
$E. n=4, \ell=0$
Choose the correct answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo