Which one of the following elements has the highest ionisation energy?

  • A
    $[Ne] \, 3s^2 \, 3p^1$
  • B
    $[Ne] \, 3s^2 \, 3p^2$
  • C
    $[Ne] \, 3s^2 \, 3p^3$
  • D
    $[Ar] \, 3d^{10} \, 4s^2 \, 4p^2$

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Similar Questions

First and second ionization enthalpies of lithium are $520 \text{ kJ mol}^{-1}$ and $7297 \text{ kJ mol}^{-1}$ respectively. Energy required to convert $3.5 \text{ mg}$ lithium $(g)$ into $Li^{2+}(g)$ [$Li(g) \rightarrow Li^{2+}(g)$] is . . . . . . $\text{kJ}$. (nearest integer) [Molar mass of $Li = 7 \text{ g mol}^{-1}$]

The correct order of second ionisation potentials $(IP)$ of $Ca$,$Ba$ and $K$ is

The first ionization enthalpies of $Mg$ and $Al$ can be expected to be

$B$ has a smaller first ionization enthalpy than $Be$. Consider the following statements:
$(I)$ It is easier to remove a $2p$ electron than a $2s$ electron.
$(II)$ The $2p$ electron of $B$ is more shielded from the nucleus by the inner core of electrons than the $2s$ electrons of $Be$.
$(III)$ The $2s$ electron has more penetration power than the $2p$ electron.
$(IV)$ The atomic radius of $B$ is more than $Be$.
(Atomic number: $B=5, Be=4$)
The correct statements are:

Why is the ionisation enthalpy of hydrogen higher than that of sodium?

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