Which one of the following group-15 hydrides | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reducing character of group-$15$ hydrides depends on the bond dissociation enthalpy of the $E-H$ bond. As we move down the group from $N$ to $

Vedclass · Accepted Answer

$BiH_3$

Vedclass · Answer

(C) The reducing character of group-$15$ hydrides depends on the bond dissociation enthalpy of the $E-H$ bond. As we move down the group from $N$ to $Bi$,the atomic size increases,which leads to a decrease in the bond dissociation enthalpy of the $E-H$ bond. Consequently,the stability of the hydrides decreases and the reducing character increases. Therefore,$BiH_3$ has the lowest bond dissociation enthalpy and is the strongest reducing agent among the group-$15$ hydrides.

Which one of the following group-$15$ hydrides is the strongest reducing agent?

Similar Questions

The structure of white phosphorus is ........ .

Select the compound in which $HCl$ is not the product of hydrolysis.

$NaH_2PO_4$ $\xrightarrow{230^\circ C}$ $Na_3P_3O_9$ $\xrightarrow{638^\circ C}$ $(NaPO_3)_n$ $\rightarrow D$ (glossy solid).
Compound $D$ is sodium hexametaphosphate,which is known as:

Phosphorus pentachloride in the solid state exists as:

$H_4P_4O_{12}$ and $H_3P_3O_9$ have the same:

Vedclass Test Series

Exam Paper Generator

Online Exam Module