Which one of the following is correct about t | vedclass

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(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $Si$ to $Pb$,the sta

Vedclass · Accepted Answer

$Pb^{2+} > Pb^{4+}$

Vedclass · Answer

(A) The stability of oxidation states in Group $14$ elements is governed by the inert pair effect. As we move down the group from $Si$ to $Pb$,the stability of the $+2$ oxidation state increases,while the stability of the $+4$ oxidation state decreases. For Lead $(Pb)$,which is at the bottom of the group,the $+2$ oxidation state is significantly more stable than the $+4$ oxidation state due to the inert pair effect. Therefore,$Pb^{2+} > Pb^{4+}$ is the correct order of stability.

Which one of the following is correct about the stability of the given ions?

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