Which one of the following is not correct?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) . Dipole moment: $H_2O_2$ $(2.1 \ D)$,$H_2O$ $(1.85 \ D)$,$NH_3$ $(1.47 \ D)$,$SF_6$ $(0 \ D)$. The order $H_2O_2 > H_2O > NH_3 > SF_6$ is correct

Vedclass · Accepted Answer

$(N-N)$ Bond length: $N_3^- > N_2H_4 > N_2$

Vedclass · Answer

(D) . Dipole moment: $H_2O_2$ $(2.1 \ D)$,$H_2O$ $(1.85 \ D)$,$NH_3$ $(1.47 \ D)$,$SF_6$ $(0 \ D)$. The order $H_2O_2 > H_2O > NH_3 > SF_6$ is correct.$B$. Bond angle: $N_3^-$ $(180^{\circ})$,$NO_2$ $(\approx 134^{\circ})$,$CF_3$ radical $(\approx 118^{\circ})$. The order $N_3^- > NO_2 > CF_3$ is correct.$C$. Bond order: $O_2^{2+}$ $(3.0)$,$O_2$ $(2.0)$,$O_2^{2-}$ $(1.0)$. The order $O_2^{2+} > O_2 > O_2^{2-}$ is correct.$D$. $(N-N)$ Bond length: $N_3^-$ $(1.18 \ \mathring{A})$,$N_2H_4$ $(1.45 \ \mathring{A})$,$N_2$ $(1.09 \ \mathring{A})$. The correct order is $N_2H_4 > N_3^- > N_2$. Thus,the statement $N_3^- > N_2H_4 > N_2$ is incorrect.

Similar Questions

The number of sigma $(\sigma)$ and pi $(\pi)$ bonds in peroxodisulphuric acid are, respectively:

The correct order of bond length is:

Which of these represents the incorrect order of the mentioned property?

The Born-Haber cycle is used to determine:

Arrange the following species in the increasing order of lone pairs of electrons:
$(A)$ $CO$
$(B)$ $NO_2^-$
$(C)$ $NF_3$
$(D)$ $CO_3^{2-}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module