Which one of the following is the most basic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation. In aromatic amines,the lone

Vedclass · Accepted Answer

$C_6H_5-N(C_2H_5)_2$

Vedclass · Answer

(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation. In aromatic amines,the lone pair is involved in resonance with the benzene ring,which decreases its availability. However,the presence of electron-donating groups (like alkyl groups) on the nitrogen atom increases the electron density on the nitrogen,thereby increasing its basicity. Comparing the given options: $C_6H_5-NH_2$ (Aniline) has no alkyl groups. $C_6H_5-NHCH_3$ has one methyl group. $C_6H_5-N(CH_3)_2$ has two methyl groups. $C_6H_5-N(C_2H_5)_2$ has two ethyl groups. Ethyl groups are better electron-donating groups than methyl groups due to the $+I$ effect. Therefore,$C_6H_5-N(C_2H_5)_2$ is the most basic compound among the given options.

Which one of the following is the most basic compound?

Similar Questions

Chloropicrin is manufactured by the reaction between $Cl_2$,$NaOH$ and

The compound that will react most readily with $NaOH$ to form methanol is

The major product $(A)$ formed in the following reaction sequence is:

Identify the products $y$ and $x$ in the following reaction sequence:
$C_6H_5CONH_2 \xrightarrow{NaOBr} y$
$C_6H_5CONH_2 \xrightarrow[(ii) H_3O^+]{(i) C_6H_5SO_2Cl / py, \Delta} x$

Predict the major product of the following reaction:

Vedclass Test Series

Exam Paper Generator

Online Exam Module