(B) Metals like $Aluminium$ and $Magnesium$ are highly reactive and are extracted by electrolytic reduction. $Copper$ is typically extracted by self-r

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(B) Metals like $Aluminium$ and $Magnesium$ are highly reactive and are extracted by electrolytic reduction. $Copper$ is typically extracted by self-reduction or pyrometallurgy. $Iron$ is extracted from its oxide ores (like $Fe_2O_3$) by thermal reduction using carbon (coke) in a blast furnace. Therefore,$Iron$ is the correct answer.

Class 12 Chemistry General Principles and Processes of Isolation of Elements Reduction to free Metal

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Which one of the following metals is extracted by thermal reduction process?

A
Copper
B
Iron
C
Aluminium
D
Magnesium

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Class 12 Questions

Class 12

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Chapter

General Principles and Processes of Isolation of Elements

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Reduction to free Metal

Which of the following is the correct chemical formula for slag?

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Steel contains $.....$ percent of carbon.

Easy

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Aluminium is extracted from alumina $Al_2O_3$ by electrolysis of a molten mixture of

Medium

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Statement $(A)$ $Mg$ can reduce $Al_2O_3$ above $1350^{\circ} C$.
Statement $(B)$ $Al$ can reduce $MgO$ below $1350^{\circ} C$.
The correct answer is

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How many moles of gaseous oxygen at one atmosphere are considered for the reaction with an element to plot a graph in an Ellingham diagram?

EasyMHT CET 2020

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Which one of the following metals is extracted by thermal reduction process?

Similar Questions

Which of the following is the correct chemical formula for slag?

Steel contains $.....$ percent of carbon.

Aluminium is extracted from alumina $Al_2O_3$ by electrolysis of a molten mixture of

Statement $(A)$ $Mg$ can reduce $Al_2O_3$ above $1350^{\circ} C$.Statement $(B)$ $Al$ can reduce $MgO$ below $1350^{\circ} C$.The correct answer is

How many moles of gaseous oxygen at one atmosphere are considered for the reaction with an element to plot a graph in an Ellingham diagram?

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Statement $(A)$ $Mg$ can reduce $Al_2O_3$ above $1350^{\circ} C$.
Statement $(B)$ $Al$ can reduce $MgO$ below $1350^{\circ} C$.
The correct answer is