Which one will liberate Br_2 from KBr? | vedclass

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(D) The ability of a halogen to displace another halogen from its salt solution depends on its oxidizing power. The oxidizing power of halogens decrea

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$Cl_2$

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(D) The ability of a halogen to displace another halogen from its salt solution depends on its oxidizing power. The oxidizing power of halogens decreases down the group: $F_2 > Cl_2 > Br_2 > I_2$.Since $Cl_2$ is a stronger oxidizing agent than $Br_2$,it can oxidize $Br^-$ ions to $Br_2$ and get reduced to $Cl^-$ ions.The reaction is: $Cl_2 + 2KBr \rightarrow 2KCl + Br_2$.Therefore,$Cl_2$ will liberate $Br_2$ from $KBr$.

Which one will liberate $Br_2$ from $KBr$?

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