Which pair of elements has the maximum electr | vedclass

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(B) Electronegativity $(E.N.)$ increases across a period and decreases down a group. Fluorine $(F)$ is the most electronegative element $(E.N. = 4.0)$

Vedclass · Accepted Answer

$Na \& F$

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(B) Electronegativity $(E.N.)$ increases across a period and decreases down a group. Fluorine $(F)$ is the most electronegative element $(E.N. = 4.0)$,while alkali metals have the lowest $E.N.$ values.Comparing the given pairs:$1$. $Li$ $(1.0)$ and $F$ $(4.0)$: Difference = $3.0$$2$. $Na$ $(0.9)$ and $F$ $(4.0)$: Difference = $3.1$$3$. $Na$ $(0.9)$ and $Br$ $(2.8)$: Difference = $1.9$$4$. $Na$ $(0.9)$ and $Cl$ $(3.0)$: Difference = $2.1$Thus,the pair with the maximum electronegativity difference is $Na \& F$.

Which pair of elements has the maximum electronegativity difference?

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