Which pair of halogens does not undergo a dis | vedclass

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Question

(A) Fluorine $(F_2)$ is a very strong oxidizing agent and it oxidizes water to oxygen $(O_2)$ or ozone $(O_3)$ instead of undergoing disproportionatio

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$F_2, I_2$

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(A) Fluorine $(F_2)$ is a very strong oxidizing agent and it oxidizes water to oxygen $(O_2)$ or ozone $(O_3)$ instead of undergoing disproportionation.$2F_2 + 2H_2O \rightarrow 4HF + O_2$Iodine $(I_2)$ is a very weak oxidizing agent and it is not strong enough to undergo disproportionation in water,as the reaction is non-spontaneous.Chlorine $(Cl_2)$ and Bromine $(Br_2)$ undergo disproportionation reactions in water to form hypohalous acids and hydrohalic acids.Therefore,the pair that does not undergo disproportionation with water is $F_2$ and $I_2$.

Which pair of halogens does not undergo a disproportionation reaction with water?

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