Which pair of the following forces will never | vedclass

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(D) The resultant $R$ of two forces $A$ and $B$ lies in the range $(A - B) \le R \le (A + B)$.For option $A$: $2 \, N$ and $2 \, N$,the range is $(2 -

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$1 \, N$ and $4 \, N$

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(D) The resultant $R$ of two forces $A$ and $B$ lies in the range $(A - B) \le R \le (A + B)$.For option $A$: $2 \, N$ and $2 \, N$,the range is $(2 - 2) \le R \le (2 + 2)$,i.e.,$0 \le R \le 4 \, N$. Since $2 \, N$ is in this range,it is possible.For option $B$: $1 \, N$ and $1 \, N$,the range is $(1 - 1) \le R \le (1 + 1)$,i.e.,$0 \le R \le 2 \, N$. Since $2 \, N$ is in this range,it is possible.For option $C$: $1 \, N$ and $3 \, N$,the range is $(3 - 1) \le R \le (3 + 1)$,i.e.,$2 \le R \le 4 \, N$. Since $2 \, N$ is in this range,it is possible.For option $D$: $1 \, N$ and $4 \, N$,the range is $(4 - 1) \le R \le (4 + 1)$,i.e.,$3 \le R \le 5 \, N$. Since $2 \, N$ is not in this range,it is impossible to obtain a resultant of $2 \, N$.

Which pair of the following forces will never give a resultant force of $2 \, N$?

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