Which product is formed on carbylamine reaction with $4$-methylaniline?

  • A
    $4-$methylbenzonitrile
  • B
    $4-$methylphenyl isocyanide
  • C
    $4-$methylnitrobenzene
  • D
    $4-$methylbenzenediazonium chloride

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Identify the major product formed from the following reaction sequence.

The correct order of basicities of the following compounds is:
$1. CH_3-C(=NH)NH_2$ (Acetamidine)
$2. (CH_3)_2NH$ (Dimethylamine)
$3. CH_3-CH_2-NH_2$ (Ethylamine)
$4. CH_3-CONH_2$ (Acetamide)

$Ph-NH_2$ $\xrightarrow[Br_2]{HNO_2} A$ $\xrightarrow[Warm]{H_2O} B$
$B$ is

Consider the following sequence of reactions. The percentage of nitrogen in the yellow product $(X)$ formed is . . . . . . %. (Nearest Integer) (Given Molar mass in g mol$^{-1}$ $H$:$1$, $C$:$12$, $N$:$14$)

When aniline is treated with sodium nitrite and hydrochloric acid at $0\,^{\circ}C$,it gives:

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