Which reaction involves a change in the elect | vedclass

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(A) The electron pair geometry is determined by the hybridization of the central atom.$A$: $\underline{B}F_3$ is $sp^2$ (trigonal planar) and $BF_4^-$

Vedclass · Accepted Answer

$\underline{B}F_3 + F^- 	o BF_4^-$

Vedclass · Answer

(A) The electron pair geometry is determined by the hybridization of the central atom.$A$: $\underline{B}F_3$ is $sp^2$ (trigonal planar) and $BF_4^-$ is $sp^3$ (tetrahedral). The geometry changes.$B$: $\underline{N}H_3$ is $sp^3$ (tetrahedral) and $\underline{N}H_4^+$ is $sp^3$ (tetrahedral). No change.$C$: $\underline{S}O_2$ is $sp^2$ (trigonal planar) and $\underline{S}O_3$ is $sp^2$ (trigonal planar). No change.$D$: $H_2\underline{O}$ is $sp^3$ (tetrahedral) and $H_3\underline{O}^+$ is $sp^3$ (tetrahedral). No change.Therefore,the correct option is $A$.

Which reaction involves a change in the electron pair geometry for the underlined element?

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